Motorola offers solid discounts on Moto X Pure Edition + Moto 360 bundles

Advertisement

Interested in Motorola’s newest flagship smartphone and the company’s second-generation smartwatch? Stop pining for yesteryear’s Black Friday and Cyber Monday deals, and pony up at least $600 before 10:59 am CT, on January 12.

The six Benjamins will get you both the unlocked Moto X Style, aka X Pure Edition, and 2015 Moto 360, obviously in entry-level configurations with 16GB internal storage and 42mm case designed for men respectively.

Bought separately outside this sweet five-day-limited promotion, the 5.7-inch handheld sets you back at least $400, while the swanky circular wearable piece costs $300 and up. The grand total is therefore normally $700, so if you hurry, you can save a cool hundred bucks.

The same discount will be applied to any bundle containing the Moto X Pure Edition and Moto 360 2, including if, say, you want the former in a 64GB flavor with genuine wood or leather covers, and the latter measuring 46mm in diameter. In that case, the third-gen X fetches $525, and the Android Wear device an additional $350, Motorola then taking $100 off your $875 bill.

If you’re willing to settle for an older, smaller, lower-end second-gen Moto X, the Lenovo-owned gadget manufacturer hooks you up with a free 32GB memory upgrade, also through January 12. Otherwise put, the 32GB version costs the same as the 16GB-er now, i.e. $300 off-contract. No coupon codes needed, no strings attached.

Source: Motorola

Advertisement

What's your reaction?
Love It
0%
Like It
0%
Want It
0%
Had It
0%
Hated It
0%
About The Author
Adrian Diaconescu
Adrian has had an insatiable passion for writing since he was in school and found himself writing philosophical essays about the meaning of life and the differences between light and dark beer. Later, he realized this was pretty much his only marketable skill, so he first created a personal blog (in Romanian) and then discovered his true calling, which is writing about all things tech (in English).